calculate the mass in milligrams of: 1) 10^21 atoms of U-238 2) 10^20 molecules of SO2 gas I know - Science - Atoms and Molecules

Question

calculate the mass in milligrams of:
1) 10^21 atoms of U-238
2) 10^20 molecules of SO2 gas

I know the step to solve this I e
1) n=N/avagadro no
m= nM = N/avgadro no M
= (10^21 / 6 022 10^23) 238g
but I am not able to simplify this :( plzz help!! in the nxt part
of the ques I am stucking when it comes to simplification
2) , (10^20 /6 02210^23) 64g

Akanksha · Accepted Answer

Dear student
Given number of atoms = 1021 atoms
Molar mass of U-238 = 238 g mol-1
Number of moles (n) = Given mass (m) Molar mass (M) n = Given number of particles (N)Avagadro number (NA) m = NNA×Mm = 10216
022×1023×238 = 39
521×10-2 g 1 g = 1000 mg Hence , mass will be 39
521×10-2×103 = 39
521×10 mg You should divide 238 by 6
022

Regards