​calculate the mass of sulphuric acid required to decompose 25g of pure marble. what is the volume of the Co2 if measured at STP

1. The reaction is as follows:

 CaCO₃ (s) + H₂SO₄(aq) $\to$ CaSO_​4(aq) + CO₂ + H₂O

1 mole of pure marble reacts with 1 mole of sulphuric acid to give 1 mole of carbon dioxide.

2. Mass of Sulphuric Acid:

   Number of moles of Calcium Carbonate = $\frac{Given mass}{Molar mass}=\frac{25}{100}=\frac{1}{4}$
 Mass of Sulphuric acid = $\frac{1}{4}\times 98=24.5 g$

3. Volume of Carbon dioxide:

 1 mole of gas at STP has volume 22.4 L

So, Volume of Carbon dioxide = $\frac{1}{4}\times 22.4 =5.6 L$