calculate the mean deviation about mean of the set of first n natural numbers when n is an odd natural number Share with your friends Share 14 Vijay Kumar Gupta answered this First find the sum of first n natural numbers where n is an oddnatural number.Note that , 1+2+3=6=3×2=3×42=3×3+12 1+2+3+4+5=15=5×3=5×62=5×5+12 1+2+3+4+5+6+7=28=7×4=7×82=7×7+12 ⋮So the sum of first n natural numbers where n is an odd natural number is, nn+12So the mean of the first n natural numbers when n is an odd natural number is, x=1n×nn+12=n+12The mean deviation about mean of the mean of first n natural numbers when n is an odd natural number is, mean deviation=∑n xi-xn =1n 1-n2+2-n2+1+⋯+n-n+12 =2n n-12n-12+12 =2n n-1n+18 = n2-14n -7 View Full Answer
