calculate the molar mass of CH3OH, Na2S2 03(given atomic mass of C=12u ,H=1u, O=16u ,Na=23u, S=32u)

Molar mass of CH3OH = (12 + 3(1) + 16 + 1) = 32 u

Molar mass of Na2S2O3 = (2(23) + 2(32) + 3(16))

  = (46 + 64 + 48)

  = 158 u

  • 4

CH3OH= 12+1(3)+16+1

              = 32u

Na2S2= 23(2)+32(2)

            =110u

  • 2
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