# calculate the molar mass of nitric acid HNO3 (H=1,N=14,O=16)

hi,

Nitric acid HNO3
H = 1.
N = 14.
O3 = 16

HNO3 = (1x1) + (14x1) + (16x 3)
= 1+ 14+ 48
=63 g/mol

HNO3 = 63.g/mol

thumbs upp lspls

• 72

NONSENSE.......

• 4

molar mass of HNO3=1+14+16*3

1+14+48=63

MOLAR MASS OF HNO3=63U

• 9

who is nonsense..ur only nonsense..taliking rubbish...my answer is laso correct only...mads are not allowed in meritnation..pls go out frm this site

• 2

here molecular mass of HNO3=63u

molar mass of HNO3=63g

• 6

hey plz understand this is the right ans we have been made to do like this.............. why don'

you reapect ans and just give thmbz down without seeing........

• 3

thu unit is gram ok...........

• -4

then u r the first person who must go out......

• 4

ffyh

• 1

Nitric Acid= HNO3

where,, Atomic mass Given as..

H- 1

N= 14

O=16

The molar mass of  HNO3= (1)+(14)+(16*3)

= 1 + 14+ 48

= 63g..ans..

• 4

MOLAR MASS OF HNO3 =(1*1)+(1*14)+(3*16)

THIS MEANS,HIDROGEN ATOM -1

NITROGEN ATOM-1

and OXYGEN ATOM-3

THEREFORE MOLAR MASS- 63 u or 63 gram..................

• 21

lol anjali and sindubhatia, stop acting like immature pricks with no life. Hold ur verbal posedown somewhere else but here. i mean come on, u guyz are in 9th grade. u should be mature as well.

u guyz are a disgrace to ur families. take my comment as an advice and don't do this ever again....

PEACE BROTHERS :)

• 1
h=1
n=14
o=16
o3=163=48
hmno3=1+14+48=72
• 2
sry 63
• -2

H - 1x1=1

N - 1X14=14

O - 3X16=48

total mass of = 1+14+48=63.

• 3
what is the mass of 1 mole of nitrogen atoms

• 9
Molar mass of nitric acid HNO3:-
Mass of hydrogen is 1 and there is one hydrogen in HNO3,so here the mass of hydrogen is 1×1=1.
Mass of nitrogen is 14 and there is only one nitrogen in HNO3,so here the mass of nitrogen is 1×14=14.
Mass of oxygen is 16 and there are 3 oxygen molecules in HNO3,so the mass of oxygen is 3×16=48.

Now,the molar mass of HNO3 is the sum of masses of hydrogen,oxygen and nitrogen.
i.e.,1+14+48==63.
• 7
What are you looking for?