calculate the no. of protons in 10g of CaCO3 . NA=6.02* 1023.
molecular mass of CaCO3 = 40+12+16*3=40+12+48
=100gm
no.of protons in one molecule of CaCO3=20+6+8*3
=50
no of protons in one mole of CaCO3i.e. 100gm of CaCO3=6.02*1023*no. of protons in one molecule
=6.02*1023*50
=301*1023
so now,
no. of protons in 10gm of CaCO3 =301*1023/10
=301*1022
hence no. of protons in 10 gm of CaCO3 will be 301*1022 protons