calculate the number of particles in each of the following:
i) 46 grams of Na atoms (NUMBER FROM MASS)
ii) 8 grams of O2molecules (NUMBER OF MOLECULE FROM MASS)
iii) 0.1 mole of carbon atoms (NUMBER OF GIVEN MOLES)

1)Atomic Mass of Na = 23 U
Therefore 1 Mole of Na = 23 grams = 6.023 X 10 23atoms
46 grams of Na = 46/23 Moles
= 2 Moles

1 Mole = 6.023 X 10 23atoms
2 Moles = 6.023 X 10 23  X  2

= 12.046 X 10 23atoms


Therefore 46 grams of Na contains 12.046 X 10 23atoms


2) Molecular Mass of O2 = 16 + 16 = 32 U (O + O)
Therefore
1 Mole of O2 = 32 grams
8 grams = 8/32 Moles
= 0.25 moles
= 0.25 X 6.023 X 10 23atoms
= 1.50 X 10 23atoms (Approximate)

Therefore 8 grams of O2 contain 1.50 X 10 23atoms

3) 1 Mole of C = 12 grams = 6.023 X 10 23atoms
0.1 Moles of C = 0.1 X 6.023 X 10 23atoms
= 6.023 X 10 22atoms

Therefore 0.1 moles of Carbon contain 6.023 X 10 22atoms

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