calculate the percentage of iron in potassium ferro cyanide K4 (Fe(CN)6)
[Fe=56, S=32, O=16, H=1, K=39, C=12, N=14]
Molar mass of K4[Fe(CN)6] = 4 X (molar mass of potassium) + molar mass of iron + 6 X (molar mass of carbon) + 6 X (molar mass of nitrogen)
= 4 X (39) + (56) + 6 X (12) + 6 X (14)
= 368 g
One molecule of K4[Fe(CN)6] contains one atom of iron. So the percentage composition of Fe is
= (mass of iron in complex / molar mass of complex) X 100
= (56 X 100) / 368
= 15.217 %