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calculate the pH of 1.0 X 10^ -8 M solution of HCL ?

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https://www.meritnation.com/ask-answer/question/what-is-the-ph-of-10-8-m-hcl-solution/chemistry/509552
 

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to calculate pH there is formula

pH=-log[H+] 

the pH will come to be 8. But we know that no acid can have pH more than 7, therefore the answer will be between 6and 7.

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 see in this we need to consider contribution of H+ from water also which is 10^ -7 (becoz both H+ and OH- conc are same and their prodcut is 10 ^ -14)...so total h+ conc is 10 ^ -7 + 10 ^ -8 = 11 *10^-8

pH = -logH+ =- log (11*10^-8) = 8-LOG11 = 8-1.0414 = 6.96(approx)

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