Calculate the volume of hydrogen liberated at STP. 500 ml, 0.5M sulphuric acid reacts with excess of zinc. According to equation Zn+H2SO4 -Zn(SO4) +H2 Share with your friends Share 11 Geetha answered this Zn + H2SO4 →ZnSO4 + H21 molar 1 L H2SO4 produces 1 mole of hydrogen = 22.4 L0.5 molar 500 ml (0.5 L) produces = 22.41 × 1 × 0.5 × 0.5 = 5.6 L of hydrogen at STP. -13 View Full Answer