Calculate the volume of hydrogen liberated at STP. 500 ml, 0.5M sulphuric acid reacts with excess of zinc. According to equation Zn+H2SO4 -Zn(SO4) +H2 Share with your friends Share 11 Geetha answered this $Zn+\hspace{0.17em}{H}_{2}S{O}_{4}\to ZnS{O}_{4}+\hspace{0.17em}{H}_{2}\phantom{\rule{0ex}{0ex}}1molar1L{H}_{2}S{O}_{4}produces1moleofhydrogen=22.4L\phantom{\rule{0ex}{0ex}}0.5molar500ml(0.5\hspace{0.17em}L)produces=\frac{22.4}{1\times 1}\times 0.5\times 0.5=5.6LofhydrogenatSTP.$ -13 View Full Answer