Calculate the volume of hydrogen released from 18g of magnesium

Solution
In the given reaction,
Mg + 2HCl → MgCl2 + H2
1 mole of Mg releases 1 mole of H2 gas on reaction with HCl.
Molar mass of Mg = 24 g
Molar volume = 22.7 L
24 g of Mg releases 22.7 L of H2 gas on reaction with HCl.
So, 1 g of Mg will release 22.724 L of H2 gas on reaction with HCl.
Hence, 18 g of Mg will release 22.724×18=17.025 L of H2 gas on reaction with HCl.

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