Calculate the weight of iron which will be converted into its oxide ( Fe3O4) by the action of 14.4g of steam on it ?
3Fe + 4H2O → Fe3O4 + H2
3 moles of Iron react with 4 moles of steam to give 1 mole of Fe3O4
Number of moles in14.4 grams of steam:
= 14.4 / 18
= 0.8 moles
Therefore number of moles of Fe that will react with 0.8 moles of steam:
= 3 * 0.8 / 4
= 0.6 moles of iron will react with 0.8 moles of oxygen
1 mole of Fe weighs 56 grams
Therefore 0.6 moles will weigh:
= 56 * 0.6
= 33.6g of Fe