calculate total no. of atoms present in 0.05 moles of glucose.

GLUCOSE is C₆H₁₂O₆
no. of molecules of glucose = no. of moles x avogadronumber = 0.05 x 6.022 x 10²³ = 3.011 x 10²²
no of atoms in one molecule of glucose = 6+12+6= 24 atoms
no. of atoms in 3.011 x 10²²molecules = 3.011 x 10²²x 24 = 7.2264 x 10²³ atoms - answer
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