can you construct a right angled triangle whose base is 4 cm and sum of its hypotenuse & other side is 8 cm.pl ans expert fast plz dont give incorrect links ans directly plz NO links

We follow these steps to construct triangle ABC from given information :

Step 1 : Draw a line BC = 4 cm

Step 2 : Take any radius ( Less than half of BC ) and center " B " we draw a semicircle that intersect our line BC at " P " . With same radius take center " P " draw an arc that intersect our semicircle at " Q " And with same radius take center " Q " draw an arc that intersect our semicircle at " R " .

Step 3 : With same radius take center " Q " and " R " draw two arcs that intersect each other at " S " .

Step 4 : Join line BS ,and extend it to " T " . we get line BT

Step 5 : Take radius of 8 cm and center " B " draw an arc that intersect our line BT at " U " .

Step 6 : Join CU .

Step 7 : Now take radius more than half of CU and cneter " C " and " U " draw two arc from both points on both side of line CU , and these arcs intersect at " X " and " Y " .

Step 8 : Join line XY that intersect line BT at " A" .

This is our required triangle ABC .

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