can you construct a right angled triangle whose base is 4 cm and sum of its hypotenuse & other side is 8 cm.pl ans expert fast plz dont give incorrect links ans directly plz NO links
We follow these steps to construct triangle ABC from given information :
Step 1 : Draw a line BC = 4 cm
Step 2 : Take any radius ( Less than half of BC ) and center " B " we draw a semicircle that intersect our line BC at " P " . With same radius take center " P " draw an arc that intersect our semicircle at " Q " And with same radius take center " Q " draw an arc that intersect our semicircle at " R " .
Step 3 : With same radius take center " Q " and " R " draw two arcs that intersect each other at " S " .
Step 4 : Join line BS ,and extend it to " T " . we get line BT
Step 5 : Take radius of 8 cm and center " B " draw an arc that intersect our line BT at " U " .
Step 6 : Join CU .
Step 7 : Now take radius more than half of CU and cneter " C " and " U " draw two arc from both points on both side of line CU , and these arcs intersect at " X " and " Y " .
Step 8 : Join line XY that intersect line BT at " A" .
This is our required triangle ABC .
2. Construct an angle of 90 degree at B and extend it to X.
3. On ray BX , mark a point P such that BP=8cm.
4. Join PC. Now draw the perpendicular bisector of PC.
5. Mark the point where the bisector meets ray BX as A.Join AB and AC.
ABC is the required triangle.Hope this helps.