# Check whether (2√2, 3√2) is a solution of 3y - 2x = 1

To show points ( 2 $\sqrt{2}$ , 3$\sqrt{2}$ ) are solution for 3

*y*- 2

*x*= 1 we substitute given values and check they are satisfied the equation or not .

3 ( 3 $\sqrt{2}$ ) - 2 ( 2 $\sqrt{2}$ ) = 1

9 $\sqrt{2}$ - 4 $\sqrt{2}$ = 1

5 $\sqrt{2}$ $\ne $ 1

So, Given points are not a solution for given equation .

Hope this information will clear your doubts about topic.

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