[Co(NH3)6]Cl2 how can we predict the overall cationic or anionic charge in any complex explain with this example
Dear student,
You need to remember the charge on the ligands that are present. NH3 has zero charge over it.
Also, you need to know the charge on the cation or the ion present along with the coordination complex. In your example, chloride ion neutralizes the charge on the coordination complex.
Since charge on each chloride ion is -1, the total charge on 2 chloride ion will be -2. Thus, if it neutralizes the complex, then defnitely the overall charge on coordination complex is +2.
Similarly from the overall charge on the complex, you can find the charge on the metal in the complex,
Co + 6 x NH3 = +2
Therefore, Co + 6 x 0 = +2
Therefore, Co = +2
Regards
You need to remember the charge on the ligands that are present. NH3 has zero charge over it.
Also, you need to know the charge on the cation or the ion present along with the coordination complex. In your example, chloride ion neutralizes the charge on the coordination complex.
Since charge on each chloride ion is -1, the total charge on 2 chloride ion will be -2. Thus, if it neutralizes the complex, then defnitely the overall charge on coordination complex is +2.
Similarly from the overall charge on the complex, you can find the charge on the metal in the complex,
Co + 6 x NH3 = +2
Therefore, Co + 6 x 0 = +2
Therefore, Co = +2
Regards