Consider the charges q,q and -q placed at the vertices of an equilateral triangle of each side l. What is the force on each charge ?
In this question can you pls tell how all the forces add upto zero .

Solution : 



FA = FAB +FAOFAB =q24πεoa2 = F  (Let's say)FAo =q24πεoa2 =FAngle between FAB and FAo =120FA =FAB2+FAo2+2FAoFAB cos 120FA =F2+F2+2F2-12 = FFB = FBA +FBOFBA =q24πεoa2 = F  (Let's say)FBO =q24πεoa2 =FAngle between FBA and FBO =120FB =FBA2+FBO2+2FBAFBO cos 120FB =F2+F2+2F2-12 =FFO = FOA +FOBFOA =q24πεoa2 = F  (Let's say)FOB =q24πεoa2 =FAngle between FOA and FOB =60FO =FOA2+FOB2+2FOAFOB cos 60FO =F2+F2+2F212 =3F

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