3 Ohms and 6 ohms are in parallel Therefore R effective = 2 Ohms. Now, 2 Ohms and 10 ohms are in series. Therefore R effective = 12 Ohms. V= I× R. 12= I × 12 = 1 Amperes.
Potential drop by 10 ohms is 10 V
Therefore 2 V is remaining
Now, Current through 3 ohms
V= I× R. 2= I × 3 = 2/3 = 0.6666667 Amperes
I hope this may have helped you a lot. Chris George.
