Consider two trains A and B such that A takes t hours to cover a stretch of 200 km. Now train B which is 25 km/h faster than A takes 24 min less than A. Find the speeds of the train A and B. Share with your friends Share 2 Varun.Rawat answered this Let the speed of train A = x km/hthen the speed of train B = x+25 km/hTotal distance to be covered = 200 kmTime taken by train A to cover 200 km = t hrs⇒200x = t .....1Time taken by train B to cover 200 km = t - 2460 hrs = t - 25 hrs⇒200x+25 =t - 25 ⇒200x+25 + 25 = t .....2Now, from 1 and 2, we get200x = 200x+25 + 25⇒200x - 200x+25 = 25⇒200x + 5000 - 200xxx+25 = 25⇒2500x2+25x = 15⇒x2 + 25x - 12500 = 0⇒x2 + 125x - 100x - 12500 = 0⇒xx + 125 - 100x + 125 = 0⇒x - 100x + 125 = 0⇒x = 100 or x = -125 rejectedSo, speed of train A = 100 km/hSpeed of train B = 100+25 km/h = 125 km/h -1 View Full Answer Etash answered this let speed of train a be x KM/H then according to question x=200/t (speed = dist/time) t=200/x For train B 24min=24/60h=2/5x+25=200/t-(2/5) X+25=200/(200/x)-(2/5) X+25=200/1000-2x/5x X+25=500x/500-x on simplifying we get 12500-x2 -25x =0 -x2-125x + 100x +12500=0 -x(x+125) + 100(x+125)=0 (x+125)(100-x)=0 so x= -125 or x= 100 since speed cannot be negative so x=100 hence speed of train A=100 and speed of train B =100+25=125 KM/H 1