Construct a square whose area is 33.64.
Answer :
To construct square whose area = 33.64 cm2
We know area of square = ( Side )2 , So
( Side )2 = 33.64
( Side )2 = 5.82
Side = 5.8 cm
Now we follow these steps :
Step 1 : Draw a line AB = 5.8 cm and extend the line AB to the right to " X " .
Step 2 : Take center " B " and any radius ( More than half of AB ) . Draw an arc on each side of B, we get two points E and F.
Step 3 : Take center " E " and any convenient width, draw an arc and with same radius and center " F " draw another arc , That intersect the previous arc at " G " .
Step 4 : Draw a line from B through G , We get line BG .
Step 5 : Take center " A " and radius length as AB , Draw an arc above point A. With same radius and center " B " draw an arc that intersect our line BG at " C " .With same radius and center " C " draw an arc that intersect our previous arc at " D ".
Step 6 : Join the lines CD and AD
We get ABCD is a square where each side has a length AB = 5.8 cm and area = 33.64 cm2
To construct square whose area = 33.64 cm2
We know area of square = ( Side )2 , So
( Side )2 = 33.64
( Side )2 = 5.82
Side = 5.8 cm
Now we follow these steps :
Step 1 : Draw a line AB = 5.8 cm and extend the line AB to the right to " X " .
Step 2 : Take center " B " and any radius ( More than half of AB ) . Draw an arc on each side of B, we get two points E and F.
Step 3 : Take center " E " and any convenient width, draw an arc and with same radius and center " F " draw another arc , That intersect the previous arc at " G " .
Step 4 : Draw a line from B through G , We get line BG .
Step 5 : Take center " A " and radius length as AB , Draw an arc above point A. With same radius and center " B " draw an arc that intersect our line BG at " C " .With same radius and center " C " draw an arc that intersect our previous arc at " D ".
Step 6 : Join the lines CD and AD
We get ABCD is a square where each side has a length AB = 5.8 cm and area = 33.64 cm2