Construct a triangle ABC in which AB=5.8cm, BC+CA=8.4cm and angle B = 60 degree.
Answer :
Step 1 : Draw a line AB = 5.8 cm
Step 2 : Take any radius ( Less than half of AB ) and center " B " we draw an arc that intersect our line AB at " P " . With same radius take center " P " draw an arc that intersect our previous arc at " Q "
Step 3 : Join line BQ And extend it to " R " .
Step 4 : Take radius of 8.4 cm and center " B " draw an arc that intersect our line BR at " S " .
Step 5 : Join AS .
Step 6 : Now take radius more than half of AS and cneter " A " and " S " draw two arc from both points on both side of line AS , and these arcs intersect at " X " and " Y " .
Step 7 : Join line XY and extend it than that intersect line BR at " C " .
This is our required triangle ABC .
Step 1 : Draw a line AB = 5.8 cm
Step 2 : Take any radius ( Less than half of AB ) and center " B " we draw an arc that intersect our line AB at " P " . With same radius take center " P " draw an arc that intersect our previous arc at " Q "
Step 3 : Join line BQ And extend it to " R " .
Step 4 : Take radius of 8.4 cm and center " B " draw an arc that intersect our line BR at " S " .
Step 5 : Join AS .
Step 6 : Now take radius more than half of AS and cneter " A " and " S " draw two arc from both points on both side of line AS , and these arcs intersect at " X " and " Y " .
Step 7 : Join line XY and extend it than that intersect line BR at " C " .
This is our required triangle ABC .