construct a triangle abc in which ab = 5 cm angle b = 60 altitude cd = 3cm
Follow the given steps to construct the ∆ABC.
Step 1: Draw the line segment, AB = 5 cm.
Step 2: Draw ∠ABX = 60° and ∠ABY = 90° at B.
Step 3: With B as centre and radius 3 cm, mark an arc intersecting the ray BY in Z.
Step 4: Draw a line passing through Z and parallel to AB. Let it intersect the ray BX in C.
Step 5: Through C, draw an altitude to AB intersecting in D. Here, CD = BF = 3 cm.
Step 6: Join AC.
Thus, ∆ABC is the required triangle.