# construct a triangle abc in which ab=5cm angle b=60 and altitude cd=3cm.Construct a triangleaqr similar to triangle abc such that the sides of triangle aqr are 3/2 of the corresponding sides of triangle abc

Follow the given steps to construct the ∆ABC.

Step 1: Draw the line segment, AB = 5 cm.

Step 2: Draw ∠ABX = 60° and ∠ABY = 90° at B.

Step 3: With B as centre and radius 3 cm, mark an arc intersecting the ray BY in Z.

Step 4: Draw a line passing through Z and parallel to AB. Let it intersect the ray BX in C.

Step 5: Through C, draw an altitude to AB intersecting in D. Here, CD = BF = 3 cm.

Step 6: Join AC. Thus,  ∆ABC is the required triangle.

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Follow the given steps to construct the ∆ABC.

Step 1: Draw the line segment, AB = 5 cm.

Step 2: Draw ∠ABX = 60� and ∠ABY = 90� at B.

Step 3: With B as centre and radius 3 cm, mark an arc intersecting the ray BY in Z.

Step 4: Draw a line passing through Z and parallel to AB. Let it intersect the ray BX in C.

Step 5: Through C, draw an altitude to AB intersecting in D. Here, CD = BF = 3 cm.

Step 6: Join AC. Thus, ∆ABC is the required triangle

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both have copied and not realised that it is not bf it is bz

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also not answered the second part of the question

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