construct a triangle abc in which ab=5cm angle b=60 and altitude cd=3cm.Construct a triangleaqr similar to triangle abc such that the sides of triangle aqr are 3/2 of the corresponding sides of triangle abc

Follow the given steps to construct the ∆ABC.

**Step 1:** Draw the line segment, AB = 5 cm.

**Step 2: **Draw ∠ABX = 60° and ∠ABY = 90° at B.

**Step 3:** With B as centre and radius 3 cm, mark an arc intersecting the ray BY in Z.

**Step 4:** Draw a line passing through Z and parallel to AB. Let it intersect the ray BX in C.

**Step 5:** Through C, draw an altitude to AB intersecting in D. Here, **CD = BF = 3 cm.**

**Step 6: **Join AC.

Thus, ∆ABC is the required triangle.