construct a triangle ABC in which BC=3cm , angle B =30 degree and AB +AC =5.2 cm.
The below given steps will be followed to draw the required triangle.
Step I: Draw the line segment BC = 3 cm and at point B, make an angle of 30°, say ∠XBC.
Step II: Cut the line segment BD = 5.2 cm (equal to AB + AC) on ray BX.
Step III: Join DC and draw the perpendicular bisector PQ of DC.
Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.