construct a triangle ABC in which BC=3cm , angle B =30 degree and AB +AC =5.2 cm.

The below given steps will be followed to draw the required triangle.

Step I: Draw the line segment BC = 3 cm and at point B, make an angle of 30°, say ∠XBC.

Step II: Cut the line segment BD = 5.2 cm (equal to AB + AC) on ray BX.

Step III: Join DC and draw the perpendicular bisector PQ of DC.

Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.

  • -5
What are you looking for?