Construct a triangle ABC, whose perimeter is 14cm and sides are in the ratio 2:3:4. Kindly send me the steps of construction
Dear Student,
Please find below the solution to the asked query:
Given : Perimeter = 14 cm , Ratio = 2 : 3 : 4
So,
Sum of terms of ratio = 2 + 3 + 4 = 9
Then ,
Length of 1st side = =3.1 cm
Length of 2nd side = = 4.7 cm
Length of 3rd side = = 6.2 cm
Now :
Step 1 : Draw a line AB = 6.2 cm
Step 2 : Take radius of length of 3.1 cm and center " A " draw an arc . With radius of length of 4.7 cm and center " B " draw an arc that intersect our previous arc at " C " .
Step 3 : Join AC and BC .
We get our required triangle ABC , As :
Hope this information will clear your doubts about Constructions .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Given : Perimeter = 14 cm , Ratio = 2 : 3 : 4
So,
Sum of terms of ratio = 2 + 3 + 4 = 9
Then ,
Length of 1st side = =3.1 cm
Length of 2nd side = = 4.7 cm
Length of 3rd side = = 6.2 cm
Now :
Step 1 : Draw a line AB = 6.2 cm
Step 2 : Take radius of length of 3.1 cm and center " A " draw an arc . With radius of length of 4.7 cm and center " B " draw an arc that intersect our previous arc at " C " .
Step 3 : Join AC and BC .
We get our required triangle ABC , As :
Hope this information will clear your doubts about Constructions .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards