construct a triangle PQR, PQ= 6cm, PR= 9cm and angle P = 120 degree
Answer :
From given information we form triangle PQR , As :
Step 1 : draw a line PQ = 6 cm
Step 2 : Take any radius ( Less than half of PQ ) and center P draw a semicircle that intersect our line PQ at " A ". With same radius and center " A " we draw an arc that intersect our semicircle at " B ". Again with same radius and center " B " we draw an arc that intersect our semicircle at " C ".
Step 3 : Join PC and extend it to " D " .
Step 4 : Take radius of 9 cm and center " P " draw an arc that intersect our line PD at " R " . Join QR
We get our required triangle PQR
From given information we form triangle PQR , As :
Step 1 : draw a line PQ = 6 cm
Step 2 : Take any radius ( Less than half of PQ ) and center P draw a semicircle that intersect our line PQ at " A ". With same radius and center " A " we draw an arc that intersect our semicircle at " B ". Again with same radius and center " B " we draw an arc that intersect our semicircle at " C ".
Step 3 : Join PC and extend it to " D " .
Step 4 : Take radius of 9 cm and center " P " draw an arc that intersect our line PD at " R " . Join QR
We get our required triangle PQR