# Construct a triangle whose sides are 4 cm,6 cm and 8 cm and bisect the smallest angle.Measure each part

Answer :

We follow these steps :

Step 1 : Draw a line AB  = 8 cm

Step 2 : Now take radius of 4 cm and center " A " draw an arc . And take radius of 6 cm and center " B "  draw an arc that intersect our previous arc at " C " .

Step 3 : Join CA and CB , we get required triangle ABC .

Now we measure all internal angles and we get $\angle$ ABC is smallest angle , So we bisect that , As :

Step 4 : Take any radius  ( Less than half of AB ) and center " B " draw an arc that intersect our line AB at " P "  and line BC at " Q " .

Step 5 : With same radius and center " P "  and " Q " draw arcs these arcs intersect at " R " .

Step 6 : Join BR and extend BR that line intersect AC at " D " .

Now we can easily measure each angles and sides . With the help of protector and scale .

• 9
26.567 degree!1
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