construct a triangleABC if its perimeter is 10.4cm and base angles 45degree and120degree
1)Draw XY = 10.4 cm
2)Draw LXY = 45 and MYX = 120
3)Draw angle bisector of LXY
4)Draw angle bisector of MYX such that it meets the angle bisector of LXY at point A.
5)Draw the perpendicular bisector of AX such that it meets XY at B
6)Draw the perpendicular bisector of AY such that it meets XY at C.
7)Join AB and AC.
Thus ABC is the required triangle.
You have to do the construction your self but the steps can be given:
step 1: Draw a line segment having measurement 10.4cm
step 2 : construct 45 and 120 degree at each point
step 3: draw the angle bisectors of each point
step 4: Extend the angle bisectors so that they meet at a point .
step 5: mark the point of intersection as A
step 6 : construct the perpendicular bisector of the angle bisectors
step 7:these perpendicular bisectors meet at two diffrent points on the line segment measuring 10.4cm
step 8: mark these two points as B and C
step 9: join A , B and C and thus you get your triangle