construct an isosceles triangle ABC with base BC=6cm, AB=AC and angle A 90degree
Here are the steps of construction:
Step 1 : Make a line BC = 6 cm as base of the triangle.
Step 2 : AB = AC, so the angles at B and C will be same and we are given ∠A = 90°
∴ ∠B = ∠C = 45°
So, make an ∠XBC = 45° at point B.
Step 3 : Now, make an ∠YCB = 45° at point C.
Step 4: Name the point as A, where these two angles meet. (Clearly, ∠A = 90°).
Thus, ∆ABC is the required ∆.