Construct triangle LMN, in which LM = 6.5cm,angle L = 900 LN+ NM = 7.7 CM. PLEASE ANSWER FAST....PLEASE DON'T GIVE ANY LINK....ANSWER DIRECTLY

Answer :

We follow these steps to construct triangle LMN from given information  :

Step 1 :  Draw a line LM =  6.5  cm

Step 2 :  Take any radius (  Less than half of LM ) and center " L "  we draw a semicircle that intersect our line LM at " P " . With same radius take center "  P "  draw an arc that intersect our semicircle at " Q " And with same radius take center "  Q "  draw an arc that intersect our semicircle at " R " .

Step 3 :  With same radius take center "  Q "  and " R " draw two arcs that intersect each other at  " S " .

Step 4 :  Join line LS ,and extend it to " T " .  we get line LT

Step 5 :  Take radius of 7.7 cm and center "  L "  draw an arc that intersect our line LT at " U " .

Step 6 :  Join MU .

Step 7 : Now take radius more than half of MU and cneter "  M " and " U "  draw two arc from both points on both side of line MU , and these arcs intersect at " X "  and " Y " .

Step 8 :  Join line XY  that intersect line LT  at "  N" . Join MN .

This is our required triangle LMN .

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first of all draw LM=6.5cmthen drawXL=7.7cm & angle XLM=90
join LM
then construct perpendicular bisector of LM let it meet LX at N
LMN is the required triangle
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