Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm

Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.
Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.
Step III: Join DC and make an angle DCY equal to ∠BDC.
Step IV: Let CY intersect BX at A. ΔABC is the required triangle.

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  1. Draw a line segment BC = 7cm.
  2. Construct ∠XBC = 75o
  3. Cut DB = 13cm from the ray BX.
  4. Join CD
  5. Make the prependicular bisectors of the line CD.
  6. Mark point A where the prependicular bisectors intersect the line BD.
  7. Join AC.
  8. Triangle ABC is the required triangle.
  9. Hope this helps you. :)
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