Correct answer is 1. Explain in detail why 1 is most reactive and why other 3 are less reactive.
Q.14. Dow's process haloarene is converted to phenol with fused NaOH. The most reactive compound is
(1)
(2)
(3)
(4) All are equally reactive
Dear Student,
In Dow's process, the first step involves the abstraction of proton. This requires the breaking of C-H bond. The order of bond strength for hydrogen and its isotopes is
C-H < C-D < C-T
So, the cleavage of C-T bond is slower than C-H bond, which decreases the reactivity (3) in comparison to (1)
Hence, (1) is most reactive.
In Dow's process, the first step involves the abstraction of proton. This requires the breaking of C-H bond. The order of bond strength for hydrogen and its isotopes is
C-H < C-D < C-T
So, the cleavage of C-T bond is slower than C-H bond, which decreases the reactivity (3) in comparison to (1)
Hence, (1) is most reactive.