# correctness of dimensitional formula v=u+at

v= Final Velocity, u= Initial Velocity, a= Acceleration and t= Time.

a= v-u/t

= at=v-u

hence, v=u+at

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Ans : The given equation is v = u + at

Dimensional formula of v = [M0LT -1]

Dimensional formula of u = [M0LT -1]

Dimensional formula of a = [M0LT -2]

Dimensional formula of t = [M0L0T]

LHS = Dimensional formula of v = [M0LT -1]

RHS = Dimensional formula of u+Dimensional formula of a x Dimensional formula of t

= [M0LT -1] + [M0LT -2] x [M0L0T]

= [M0LT -1] + [M0LT -1]

= 2 [M0LT -1]

Since, 2 is a dimensionless constant.

Therefore, LHS = RHS

Hence, the given relationship(equation) is dimensionally correct.

• 28

check the correctness of the following equation using dimension method

V=u+at T=rhpg/2 F=ma

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• 1
The given equation is v = u + at

Dimensional formula of v = [M0LT?-1]

Dimensional formula of u = [M0LT?-1]

Dimensional formula of a = [M0LT?-2]

Dimensional formula of t = [M0L0T]

LHS = Dimensional formula of?v?= [M0LT?-1]

RHS = Dimensional formula of?u+Dimensional formula of?a?x Dimensional formula of?t

? =?[M0LT?-1] + [M0LT?-2] x [M0L0T]

? = [M0LT?-1] + [M0LT?-1]

? = 2 [M0LT?-1]

Since, 2 is a dimensionless constant.

Therefore, LHS = RHS

Hence, the given relationship(equation) is dimensionally correct.
• 4
Here in this equation ,
V=U + at
V stands for final velocity and the dimensional formula for velocity is [M0LT-1].

stands for initial velocity and the dimensional formula for velocity is [M0LT-1]
a stands for the acceleration of the partical and thr dimensional formula of a is [M0LT-2]

therefore LHS =[M0LT-1] =- RHS

hence the given formula is correct
• 0
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