cosA - sinA + 1 / cosA + sinA - 1 = cosecA + cotA

which ex question is this

Lol

Lel

This answer doesn't make sense

Its simple guys just divide the equation with sin

4th line is not understand other good

Evaluate, cos48-sin42 Ans: cos a=sin(90-48) = sin42 So, sin42-sin42=0

Ask me any question of trigo I am IIT TOPPER

Q.I f 7sin^2A+3cos^2A=4; then show that tanA=1/√3 HERE IS THE ANSWER:- Tried to solve similar questions on the spot in my exams without any practice!!!

(cosA - sin A + 1)/(cosA + sinA - 1)
Divide numerator and denominator by sinA, we get
=(cosA/sinA - sinA/sinA + 1/sinA)/ (cosA/sinA + sinA/sinA - 1/sinA)
=(cotA - 1 + cosecA)/(cotA+1- cosecA)
= ​(cotA + cosecA- 1)/cotA + 1 - cosecA)​
We know that cosec²A - cot²A= 1
so we replace 1 by cosec²A - cot²A, we get
=[cotA + cosecA - (cosec²A - cot²A)]/(cotA - cosecA + 1)
=[(cotA + cosecA)- (cosecA - cotA)(cosecA+cotA)]/(cotA -cosecA + 1)
taking cosecA + cotA common, we get
=cosecA + cotA[1-(cosecA - cotA)]/(cotA - cosecA + 1)
=cosecA + cotA(1-cosecA + cotA)/(cotA - cosecA +1)
=cosecA + cotA  Proved         {1-cosecA + cotA cancelled out}

(1+sin theta +cos theta /1-sin theta +cos Theta) 2 =1-cos /1 +cos

I am a new member of this meritnation. .com Actually i want to ask a que Can anyone help me plzz!!! Prove that Question no. 19

thank you

CosA/1+sina + 1+sinA/cosA =2sinA Prove it

Sorry to say but guys I can't even understand a single woemrd u all have wrote here I want answer in easy and simple language that's why I had logged in to Meritnation ...

Can anyone ans me the 24th 3rd ques

I suck.

Here's a simple solution :)

I f 7sin^2A+3cos^2A=4; then show that tanA=1/√3 For this question, there is a better answer 4sin^2a +3sin^2a +3cos^2 a =4 4 sin^2 a +3 =4 4 sin^2a =1 Sin^2a = 1/4 Sina = 1/2 a = 30

I hope its helpful

Here is the answer.