d,e,f are the mid points of the sides bc, ca,and ab respectively of triangle abc. then triangle def is congruent to triangle:

  1. triangle abc
  2. triangle aef
  3. triangle bfd,cde
  4. triangle afe,bfd,cde

The following figure explains the situation given:

Note that FE will be parallel to BC and also half of it. This can be understood by learning the mid-point theorem and its converse.
Hence, FE = BD = DC.
Similarly, ED = QF = FB and FD = AE = EC.
Hence by SSS we have the four triangles DEF, AFE, FBD and EDC congruent. Option 4 is correct.

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give the anwer plz

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