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De-broglie wavelength associated with an electron accelerated through a potential difference V is lambda. , what will b its wavelength , when accelerating potential is increased to 4V.

Here, why cant we use the formula '' lambda= 1.22/root V '' and this formula is applicable in what type of quests.?

We know for electron,
λ=12.25 AoV  ..............(1)for potential difference 4Vλ'=12.25 Ao4V=1212.25 AoV=12λ
Hence wavelength become half of initial wavelength.
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you can use the formula here and you will get almost the very same answer as you will get from the formula

lambda=h/root(2mqV)

You can check with both formulas and answer should match.

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