Dear experts find the probability distribution of no of success in 3 tosses of a die where success is defined as six appears on at least 2 dice . No links pls Share with your friends Share 0 Neha Sethi answered this Dear student When a die is tossed three times, we obtain (6×6×6)=216 number of observationsLet X be the random variable ,which represents the number of successes.Here, success means six appears on atleast two dice.P(X=2)=P(six appears on atleast two of the dice)=16×56×56+56×16×56+56×56×16=25+25+25216=75216=2572P(X=3) =P(six appears on all three of dice)=16×16×16=1216Thus, the required probability distribution is as follows: X 2 3 P(X) 25/72 1/216 Regards 0 View Full Answer Reena answered this Please find this answer 0