Derive an expression for the focal length of the combination of two thin lenses when they are SEPERATED by a small distance?
Consider two lenses L1 and L2 separated by a small distance 'd' apart, as shown below. A ray of light AB initially parallel to the principal axis hits the lens L1 and deviates and then hits lens L2.
here
f1 is the focal length of L1 and
f2 is the focal length of L2
and
δ1 is the deviation produced by L1
δ2 is the deviation produced by L2
so,
form simple geometry
δ1 = h1 / F1
and
δ2 = h2 / F2
now,
total deviation of the ligth ray will be
δ = δ1 +δ2
or
δ = (h1 / F1) + (h2 / F2)
also
at lens 2 and triangle BCD
h2 = h1 - CD = h1 - BD.tanδ1
or
h2 = h1 - d.tanδ1
now as δ1 is very small, tanδ1 ~ δ1
thus,
h2 = h1 - d.δ1
so, from earlier relation
h2 = h1 - d.(h1/f1)
thus,
δ = δ1 +δ2 = (h1/f1) + [(h1 - d.(h1/f1)) / f2]
or
δ = (h1/f1) + (h1/f2) - (dh1 / f1.f2)
now,
for the combination of the two lenses let F be the combined focal length.
So, the total deviation will be given as
δ = h1 / F
or
(h1/f1) + (h1/f2) - (d.h1 / f1.f2) = h1 / F
thus,
1/F = 1/f1 + 1/f2 - (d / f1.f2)
so, the combined focal length will be
F = f1.f2 / (f1 + f2 - d)