determine the point on graph of linear equation 2x+5y=19, whose ordinate is1 1/2 times its abscissa.
According to the given statement, y - coordinate = 1 1/2 (X-coordinate) = 3/2 of X. Now, the value of y in eq. 2x+5y=19 will be = 3/2 of X. Therefore, 2x+5y=19 2x+5×3/2x = 19 2x+15x/2 = 19 2x+15x = 38 17x = 38 x = 38/17 = 2 (approx) Hence, the point is (2,3). Now place it on the graph. Hope, you understand it very well.