determine the points in yz -plane and xz-plane which are equidistant from points A(1,-1,0), B(2,1,2) and C (3, 2 ,-1).
let the point P(0,b,c) is in y-z plane such that its distances from the points A(1,-1,0) , B(2,1,2) and C(3,2,-1) are equal.
therefore
PA = PB and PB = PC
solving eq(1) and eq(2), we have:
therefore the required point in y-z plane is
similarly by assuming the point Q(x,0,z) in x-z plane we can find the another point in x-z plane
hope this helps you
therefore
PA = PB and PB = PC
solving eq(1) and eq(2), we have:
therefore the required point in y-z plane is
similarly by assuming the point Q(x,0,z) in x-z plane we can find the another point in x-z plane
hope this helps you