Determine the value of the de Broglie wavelength associated with the electron orbiting in the ground state of hydrogen atom. How will the de Broglie wavelength change when it is in the first excited states. Share with your friends Share 9 Vipra Mishra answered this Dear Student The enrgy of nth state of hydrogen atom is given byEn=-13.6n2So in ground state n = 1E1= -13.6 eVTherefore λ= hcE=6.63×10-34×3×10813.6×1.6×10-19 J=914.0 AWhen atom is in first excited state n = 2So energyE2= -13.64 eV=-3.4 eVChange in energy = E2-E1 =-3.4eV +13.6eV =10.2eVTherefore change in wavelength∆ λ= hc∆E=6.63×10-34×3×10810.2×1.6×10-19 J=1218.7A 45 View Full Answer Selvan answered this Use the standard radius equation for hydrogen r=5.29∗10−11∗n2r=5.29∗10−11∗n2 where nn is the shell number. Take this as the max wavelength the electron should have. -1
