1. differentiate sin -1 (2x+1.3x)/1+36x.
2. all in powers.

Hey Hari,

take 6^x=t

sin^(-1) { 2^(x+1).3^x) / 1+36^x

=sin^(-1) { 2^x.2.3^x) / (1+6^(2x))

=sin^(-1) { 2.6^x) / (1+6^(2x))

=sin^(-1) { 2t / 1+t^2}

now take t=tany

=sin^(-1) { 2tan y / 1-(tan^2) y)}

now the quantity within the bracketts is sin2y

so sin^(-1) { sin2y}=2y

=2t

=2(tan^(-1)x)

now differentiate wrt to x

=2/(1+x^2)

=2tan