Divide 40 into two parts such that 1/4th of one part is 3/8th of the other.

Dear Student ,
Please find below required solution
let one part be x
so other part will be 40 - x

from given condition
$$\begin{gathered} x \times \frac{1}{4} = (40 -x )\hspace{0.17em}\times \frac{3}{8} \\ \Rightarrow 2x = 3 (40 -x )\hspace{0.17em} \\ \Rightarrow 2x = 120 - 3x \\ \Rightarrow 5x = 120 \\ \Rightarrow x = 120/5 = 24 \\ and 40 - x = 40 - 24 = 16 \end{gathered}$$

hence two required numbers are 24 and 16.

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