Divide 41 into two positive parts such that difference of their squares is 369.

 Let one of the numbers be x
Therefore, the other number = (41 - x)

According to given condition,

x2 - (41 - x)2 = 369
x2 - 1681 - x2 + 82x = 369
82x = 2050

x = 25 

One no. is 25 and the other no. is (41-25) = 16. ANS.

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 let the parts be x and y

x+y=41

x2-y2=369

(x+y)(x-y)=369

41(x-y)=369

x-y=9

x+y=41

on adding

2x=50

x=25

y=41-x

y=41-25

y=16

parts are 25 and 16

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