!!!DO NOT SEND ANY LINKS .Answer the 9th question
Q.9. A uniform metre scale can be balanced at the 70.0 cm mark when a mass of 0.05 kg is hung from 94.0 cm mark.
(i) Draw a diagram showing the arrangement.
(ii) Find the mass of the metre scale.
(Ans. 0.06 kg)
Dear Student ,
We can comment that Torque = F X r(read as F crossed r)
F = mg = weight of the object
Assuming the mass of the scale to be M.
Taking that the mass of the scale is concentrated in the centre of the scale. So, its at the 50 cm mark.
By balancing of the torques, 0.5 x 24 x g = M x 20 x g
So, M = 0.6 kg
Regards
We can comment that Torque = F X r(read as F crossed r)
F = mg = weight of the object
Assuming the mass of the scale to be M.
Taking that the mass of the scale is concentrated in the centre of the scale. So, its at the 50 cm mark.
By balancing of the torques, 0.5 x 24 x g = M x 20 x g
So, M = 0.6 kg
Regards