Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an angle of 60°. Give the justification of the construction.

The tangents can be constructed in the following manner:

**Step 1**

Draw a circle of radius 5 cm and with centre as O.

**Step 2**

Take a point A on the circumference of the circle and join OA. Draw a perpendicular to OA at point A.

**Step 3**

Draw a radius OB, making an angle of 120° (180° − 60°) with OA.

**Step 4 **

Draw a perpendicular to OB at point B. Let both the perpendiculars intersect at point P. PA and PB are the required tangents at an angle of 60°.

**Justification**

The construction can be justified by proving that ∠APB = 60°

By our construction

∠OAP = 90°

∠OBP = 90°

And ∠AOB = 120°

We know that the sum of all interior angles of a quadrilateral = 360°

∠OAP + ∠AOB + ∠OBP + ∠APB = 360°

90° + 120° + 90° + ∠APB = 360°

∠APB = 60°

This justifies the construction.

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