draw a triangle abc in which ab=5 cm bc=6 cm and angle abc= 60 degrees

construct another triangle similar to triangle abc with scale factor 5/7 { 5 upon 7 }

We follow these steps to construct angle ABC .

Step 1 : Draw a line BC = 6 cm .

Step 2 : Now take any radius ( Less than half of BC ) and take center " B " draw an arc that intersect our line BC at " P " , With same radius and center is " P " draw another arc that intersect our previous arc at " Q " .

Step 3 : Join BQ and extend it to D

Step 4 : Take radius = 5 cm and center " B " we draw an arcs that intersect our line BD at " A " Now we join AC , and get triangle ABC .

Now We construct another triangle with scale factor $\frac{5}{7}$ , As :

Step 5 : Draw a line BX As $\angle $ CBX is any acute angle and draw seven equal radius arc on line BX that intersect at X

_{1}. X

_{2}, X

_{3}, X

_{4}, X

_{5}, X

_{6}and X

_{7}AS :

BX

_{1}= X

_{1}X

_{2}= X

_{2}X

_{3}= X

_{3}X

_{4}= X

_{4}X

_{5}= X

_{5}X

_{6}= X

_{6}X

_{7}

Step 6 : Join X

_{7}

_{ }to C and than draw a line from X

_{5}as parallel to X

_{7}C that intersect our line BC at C' .

Step 7 : Draw line from C' as parallel to AC that intersect line AB at A' .

We get triangle A'BC' whose sides are $\frac{5}{7}$ of corresponding sides of triangle ABC .

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