Draw an isosceles triangle ABC with AB = AC and base BC = 7 cm and vertical angle is 120°. Construct triangle AB´C´ ~ triangle ABC with its sides 1 1/ 3 times of the corresponding sides of  triangle ABC.

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Please find below the solution to the asked query:

First construct ABC using the following steps:1. Draw a base BC=7 cm.2. The vertical angle is A=120°. Here ABC is isosceles triangle.Since the other two angles are equal, we have   A+B+C=180°   120°+B+B=180°    2B=180°-120°    2B=60°    B=30°So we get,B=C=30°3. So contruct B=C=30° which intersect each other at point A.Then we get ABCNow we will construct a triangle similar to ABC whose sides are 113=43 ofsides of ABC.Follow the folowing steps:1. Draw a ray BX inclined at an acute angle with BC.2. Mark points X1,X2, X3, X4  on BX such that  BX1=X1X2=X2X3=X3X43. Join CX34. From X4, draw a line parallel to CX3 which intersects BCproduced at C'5. Again from C', draw a line parallel to AC which intersects BAproduced at A'Then A'BC' is the required similar triangle.

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