# draw the graph of 2x+y=6 and 2x-y+2=0.shade the regions bounded by these lines at x axis.find the area of shaded region.

sorry by mistake i have putted thumb down. it's really good answer.

• -18
6(ax+by)=3a+ab ; 6(bx-ay)=3b-2a find x and y

• -3
y did u multiply 2nd equation by 2

• 11
Can anyone give the full answer for this question plzz I didn't understood 😊

• -6
IN FIRST EQUATION
TAKE x=1 THAT MEAN y=4
x=2  i.e. y=2
MARK THE POINT OF BOTH EQUATION ON THE GRAPH

• -6

Given equations are:

2x + y  6 = 0 ... (1)

2x  y + 2 = 0 ... (2)

Solution for 2x + y  6 = 0 are (2, 2), (0, 6) and (3, 0).

Solution for 2x  y + 2 = 0 are (2, 6), (1, 4) and (3, 8).

The graph for the equations can be drawn as follows: Co-ordinates of vertices are (1, 4), (-1, 0) and (3, 0).

Area = (½)x base x height

= (1/2) x 4 x 4

= 8 sq units
• 4

Given equations are:

2x + y  6 = 0 ... (1)

2x  y + 2 = 0 ... (2)

Solution for 2x + y  6 = 0 are (2, 2), (0, 6) and (3, 0).

Solution for 2x  y + 2 = 0 are (2, 6), (1, 4) and (3, 8).

The graph for the equations can be drawn as follows: Co-ordinates of vertices are (1, 4), (-1, 0) and (3, 0).

Area = (½)x base x height

= (1/2) x 4 x 4

= 8 sq units
• 33
👍👍👍👍
• -1
How do you find solutions.. Plz tell
• -5
Sandesh G has answered the question correctly.
• 0
What are you looking for?