Draw the graphs of following equations on the same graph sheet:

x-y=0, x+y=0, y+5=0

Also, find the area enclosed between these lines.

ABC is the required area:

area of triangle ABC = 1/2 * BC * height

$=\frac{1}{2}*(5-(-5\left)\right)*5\phantom{\rule{0ex}{0ex}}=\frac{1}{2}*10*5\phantom{\rule{0ex}{0ex}}=25squareunits$

hope this helps you

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